2x^2=14x+60

Solution for 2x^2=14x+60 equation:

2x^2=14x+60

We move all terms to the left:

2x^2-(14x+60)=0

We get rid of parentheses

2x^2-14x-60=0

a = 2; b = -14; c = -60;
Δ = b2-4ac
Δ = -142-4·2·(-60)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-26}{2*2}=\frac{-12}{4}
=-3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+26}{2*2}=\frac{40}{4}
=10
$